Summation Calculator – Add Up a Whole Series in One Step

Adding 1 + 2 + 3 all the way to 100 by hand is slow and easy to mess up. Pick a pattern, set the start and the end, and this calculator gives the exact total with closed-form working and a term-by-term table, so you can see every step.

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Your series

Whole numbers only. Start and end can be negative, but start must not be larger than end.

Your numbers never leave this page. Everything is calculated in your browser.

Result

Sum
5,050
Σk from k = 1 to 100.

The numbers behind it

Number of terms100
First term1
Last term100
Closed form usedn(n + 1) ÷ 2, with n = 100 minus n = 0
kTermRunning total

The table shows the first 20 terms. The sum itself always uses the closed form, so it stays exact even for very long ranges.

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Key Takeaways
  • Closed forms, not term-by-term adding: the sum of k from 1 to 100 is 100 × 101 ÷ 2 = 5,050, over 100 terms, exact even for 10,000 terms.
  • Any range comes from subtraction: the sum of k from 5 to 8 is 36 − 10 = 26, and the term table shows only the first 20 terms.
  • Only five patterns are offered — k, k squared, k cubed, a constant, and ak + b — and every sum can be checked by its term count (b − a + 1) and its first and last terms.

How the sum builds up

Each row adds one more term to the running total. For the default series, Σk from 1 to 100, the running total after the first ten terms is already 55, and it keeps growing by one more than the last step each time.

Reading the bars: the first ten terms of the current series, each bar sized by the running total at that point. When terms grow fast, as with cubes, the later bars shoot up much quicker.

How it works, in three steps

1

Pick the pattern

Choose k, k squared, k cubed, a constant, or a linear pattern ak + b. The calculator only offers these five patterns, and says so openly.

2

Set the range

Type the start and end values of k. For the classic example, start at 1 and end at 100.

3

Read the closed form

The total comes from a formula, not from adding thousands of terms one by one, so it is exact even for a range of 10,000 terms.

How the calculation works

Σk = n(n + 1) ÷ 2 · Σk² = n(n + 1)(2n + 1) ÷ 6 · Σk³ = [n(n + 1) ÷ 2]²

Worked example. Σk from 1 to 100: using n = 100, the formula gives 100 × 101 ÷ 2 = 5,050. That is the famous result Gauss is said to have found as a schoolboy by pairing 1 with 100, 2 with 99, and so on into 50 pairs of 101.

Squares example. Σk² from 1 to 10: using n = 10, the formula gives 10 × 11 × 21 ÷ 6 = 385. You can check it by hand: 1 + 4 + 9 + 16 + 25 + 36 + 49 + 64 + 81 + 100 = 385.

Ranges that do not start at 1. A sum from k = a to k = b is the sum from 1 to b minus the sum from 1 to a − 1. For example, Σk from 5 to 8 is (8 × 9 ÷ 2) − (4 × 5 ÷ 2) = 36 − 10 = 26, and indeed 5 + 6 + 7 + 8 = 26.

Constant and linear patterns. Σa over n terms is just a × n, so Σ7 from 1 to 50 is 350. Σ(ak + b) splits into a × Σk plus b × n, so Σ(2k + 1) from 1 to 10 is 2 × 55 + 1 × 10 = 120.

Going deeper

Adding term by term works for short lists, but it gets slow and error-prone as the range grows, and a computer adding thousands of floating point numbers can drift by tiny rounding amounts. A closed form jumps straight to the answer with a few multiplications, so it is both faster and exact for whole-number inputs. This calculator still shows the first 20 terms one by one, because seeing the terms build up is the best way to trust the formula.

An open expression box sounds flexible, but it hides real problems: ambiguous notation, unsupported functions, and answers that look exact but are not. This calculator covers the five patterns that cover most school and worksheet problems, and it names each pattern and its formula openly. If your series is something else, like a geometric series or a series with fractions, it needs its own tool with its own formula, not a guessed parse of your typing.

Five patterns, five formulas, and the numbers that prove them

This calculator covers five patterns, and it names each pattern and its formula openly: k, k squared, k cubed, a constant, and a linear pattern ak plus b. That closed list is a deliberate limit, not an oversight. An open expression box would hide real problems: ambiguous notation, unsupported functions, and answers that look exact but are not. Five patterns cover most school and worksheet problems, and each one comes with a closed form, so the total is exact even for a range of 10,000 terms, without adding thousands of terms one by one.

The classic pattern is k, and its closed form is n times n plus 1, divided by 2, where n is the number of terms when the range starts at 1. From 1 to 100, that gives 100 times 101 divided by 2, which is 5,050, the famous result Gauss is said to have found as a schoolboy by pairing 1 with 100, 2 with 99, and so on into 50 pairs of 101. Starting at 0 instead of 1 changes nothing for this pattern: the sum from 0 to 100 is also 5,050, across 101 terms, because the added term is 0. That is a useful sanity check for any range that starts at 0: the zero term contributes nothing, so the total must equal the total from 1.

Squares use n times n plus 1 times 2n plus 1, divided by 6. From 1 to 10, that gives 10 times 11 times 21 divided by 6, which is 385, and you can check it by hand: 1 plus 4 plus 9 plus 16 plus 25 plus 36 plus 49 plus 64 plus 81 plus 100 is 385. From 1 to 100, the same formula gives 338,350, a number no one would want to add by hand, and the closed form delivers it exactly. Cubes use the square of the k formula: the sum of cubes from 1 to n is n times n plus 1 divided by 2, all squared. From 1 to 10, that gives 3,025, and from 1 to 100 it gives 25,502,500. The cubes case is the most dramatic demonstration of why closed forms matter: adding a hundred cubes by hand invites error at every step, while the formula needs two multiplications.

Constants and linear patterns split into even simpler pieces. The sum of a constant a over n terms is just a times n, so the sum of 3 from 1 to 10 is 30, and the sum of 7 from 1 to 50 is 350, as the base guide states. A linear pattern ak plus b splits into a times the sum of k, plus b times the number of terms. The probed linear case, 7k plus 1 from 1 to 100, gives 35,450: 7 times 5,050 is 35,350, plus 1 times 100 is 100, totalling 35,450, matching the display exactly. Another probed case, 3k plus 2 from 1 to 10, gives 185: 3 times 55 is 165, plus 2 times 10 is 20, totalling 185, again matching the display. And 3k plus 2 from 1 to 100 gives 15,350, by the same split: 3 times 5,050 is 15,150, plus 200 is 15,350.

PatternRangeClosed formSum
k1 to 100n(n + 1) ÷ 25,050
k0 to 100n(n + 1) ÷ 2, range difference5,050
k squared1 to 10n(n + 1)(2n + 1) ÷ 6385
k squared1 to 100n(n + 1)(2n + 1) ÷ 6338,350
k cubed1 to 10[n(n + 1) ÷ 2] squared3,025
k cubed1 to 100[n(n + 1) ÷ 2] squared25,502,500
Constant 31 to 10a × n30
7k + 11 to 100a × Σk + b × n35,450
3k + 21 to 10a × Σk + b × n185
3k + 21 to 100a × Σk + b × n15,350

Every figure in that table is a displayed result from this page’s own calculator. The 0-to-100 row carries the note “range difference” in its closed-form label, because the calculator computes a range that does not start at 1 by subtracting sums from 1, and that method is the subject of the next section.

Ranges that do not start at 1, and why the table stops at 20 terms

A sum from k equals a to k equals b is the sum from 1 to b minus the sum from 1 to a minus 1. That single sentence handles every range on this page, and the base guide’s example shows it: the sum of k from 5 to 8 is the sum from 1 to 8 minus the sum from 1 to 4, which is 36 minus 10, giving 26, and indeed 5 plus 6 plus 7 plus 8 is 26. The method works for every pattern, not just k, because each pattern’s closed form gives the sum from 1 to any endpoint, and subtraction does the rest. It also explains the 0-to-100 row in the previous table: the sum from 0 to 100 is the sum from 1 to 100 plus the zero term, which is 5,050 plus 0, giving 5,050, across 101 terms rather than 100.

That subtraction method is also why the calculator can be exact for very long ranges. Adding term by term works for short lists, but it gets slow and error-prone as the range grows, and a computer adding thousands of floating point numbers can drift by tiny rounding amounts. A closed form jumps straight to the answer with a few multiplications, so it is both faster and exact for whole-number inputs. The calculator still shows the first 20 terms one by one, because seeing the terms build up is the best way to trust the formula, but the sum itself always uses the closed form, so it stays exact even for very long ranges. The table of terms is a teaching aid, not the computation, and the sum does not depend on how many terms the table shows.

Why 20 terms, then, and not all of them? Because a table of 10,000 terms would be unreadable, and its purpose, showing how the series builds, is served by the first 20. The running totals in those 20 rows let you verify the formula’s early behaviour: the k table from 1 to 100 begins 1, 3, 6, 10, 15, and each running total matches the closed form for its own endpoint. If a later term worried you, the closed form, not the table, is the place to check it, because the table deliberately stops where readability stops. A sum that needs the 5,000th term is still exact, because the formula never needed to list it.

What happens if the start is bigger than the end? The range is empty in the usual reading, so this calculator shows an error and asks you to fix the range instead of guessing an answer, exactly as its own questions state. There are no terms from, say, 10 down to 1 in the calculator’s forward-counting patterns, and the sensible response is to swap the endpoints or to reconsider what series you meant. Do not treat an error as a sum, and do not work around it by typing a range you do not mean: a sum over no terms and a sum over a reversed range are different ideas, and the calculator’s patterns assume the start comes first. If your series genuinely runs downward, rewrite it as a forward series with a transformed pattern, or use a tool that models direction explicitly.

Checking any sum on this page, by hand and by formula

Three checks catch most errors. First, check the term count: the number of terms from a to b inclusive is b minus a plus 1, so 1 to 100 has 100 terms, 0 to 100 has 101 terms, and 5 to 8 has 4 terms. A term count that disagrees with that arithmetic means an endpoint was mistyped. Second, check the first and last terms: for k from 1 to 100, the first term is 1 and the last is 100, and the result panel reports both, so a last term that does not match your endpoint means the pattern or the range is not what you intended. Third, check a small case by hand: compute the same pattern over 1 to 10 by adding the terms, and compare with the calculator. If the small case matches, the formula is right, and any disagreement on a large case is an endpoint error, not a formula error. If the small case disagrees, the pattern is wrong, and no large case can be trusted until it is fixed.

Where these formulas show up, and how to remember them

The k formula shows up wherever things accumulate one by one: the sum of the first n counting numbers is the nth triangular number, so 1 plus 2 plus 3 plus 4 plus 5 is 15, the fifth triangular number, and the same pairing that gives 5,050 for 1 to 100 gives 15 for 1 to 5. The squares formula shows up in geometry and in statistics, where sums of squares measure area-like quantities and variation. The cubes formula, that the sum of cubes is the square of the sum, is the most surprising of the five: the sum of the first 10 cubes is 3,025, which is 55 squared, and 55 is the sum of the first 10 counting numbers, so the cubes total is literally the square of the counting total. Remembering that relationship, cubes total equals counting total squared, is the easiest way to remember the cubes formula, and it checks out for every n, not just 10: for 1 to 100, the counting total is 5,050, and 5,050 squared is 25,502,500, the cubes total.

The constant and linear formulas show up in the most ordinary places: a fixed charge repeated n times is a constant sum, and a charge that grows by a fixed step each time is a linear sum. A subscription at a fixed monthly price over n months is the constant pattern. A payment that starts at b and rises by a each period is the linear pattern, and its total splits into a times the counting total plus b times the number of periods, exactly as the calculator’s linear case does. Recognising which pattern a real problem matches is the whole skill: once the pattern is named, the formula is fixed, and the calculator does the rest. If the problem matches none of the five patterns, the honest move is to find the tool for its pattern, not to force it into one of these five.

A last word on exactness. The closed forms on this page are exact for whole-number inputs, which means the calculator’s answers are exact, not approximate, for every range it covers. That exactness is the point of closed forms: adding a hundred terms by hand invites an error at every step, while a formula with two or three multiplications invites an error only if the formula itself is wrong, and these five formulas have been checked for centuries. When you use this calculator, you are using mathematics that predates computers by hundreds of years, delivered instantly. The table of the first 20 terms is there so you can watch the series build and trust the formula, not because the formula needs the table. Trust the formula, check it on a small case, and let the calculator handle the large ones.

More ranges, worked by subtraction, and checked by hand

The subtraction method from the earlier section handles every range, and working two more ranges by hand shows how reliable it is. The sum of k squared from 5 to 8 is the sum from 1 to 8 minus the sum from 1 to 4. The sum from 1 to 8 is 8 times 9 times 17 divided by 6, which is 204, and the sum from 1 to 4 is 4 times 5 times 9 divided by 6, which is 30, so the range total is 204 minus 30, which is 174. Check it by adding the terms: 25 plus 36 plus 49 plus 64 is 174, matching exactly. The subtraction method and the direct addition agree, as they must, because both compute the same four terms, and the agreement is the check that the closed form was applied correctly.

Larger ranges work the same way, with the closed form doing the heavy lifting. The sum of k from 1 to 50 is 50 times 51 divided by 2, which is 1,275, and you can check the shape of that answer against the 1-to-100 case: half the range, roughly a quarter of the total, since the total grows with the square of n, and 1,275 is indeed close to a quarter of 5,050, differing only because the formula uses n times n plus 1 rather than n squared. The sum of k squared from 1 to 50 is 50 times 51 times 101 divided by 6, which is 42,925. No one would add fifty squares by hand without error, and no one needs to: the formula gives the exact total in three multiplications and a division, and the small-case check, 1 to 10 giving 385, confirms the formula before it is trusted on the large case.

That two-step discipline, check small, trust large, is the whole method for this calculator. Compute the pattern over 1 to 10 by hand, compare with the display, and if they match, the formula is right and any disagreement on a large range is an endpoint error. Compute the term count as end minus start plus 1, and compare with the display. Read the first and last terms from the result panel, and compare with your endpoints. A sum that passes those three checks is exact, because the closed form is exact, and the only remaining errors are typing errors, which the checks are designed to catch. A sum that fails one of them should be retyped, not trusted, because the calculator’s formulas do not fail: only the inputs do.

Reading sigma notation without fear

Sigma notation looks forbidding, but it reads plainly once its three parts are named. The symbol itself, the capital Greek letter sigma, means add up. Below it sits the starting value of the index, usually written as k equals some number, and above it sits the ending value. Beside it sits the pattern, the expression in k whose values are added. So the sum of k from 1 to 100 is written with sigma, k equals 1 below, 100 above, and k beside, and it means add 1 plus 2 plus 3, all the way to 100, giving 5,050. The sum of 7k plus 1 from 1 to 100 is written the same way, with 7k plus 1 beside the sigma, and it means add 8 plus 15 plus 22, all the way to 701, giving 35,450. Once the three parts are named, every sigma expression on this page reads as a sentence: add the pattern, from the start, to the end.

Sigma notation: reading and writing sums

Sigma notation compresses a sum into one expression: Σ from i = 1 to n of aᵢ means a₁ + a₂ + … + aₙ. The index variable (i) takes each integer value from the lower limit to the upper limit, the expression after the sigma is evaluated at each value, and the results are added. Σ from i = 1 to 5 of i² means 1 + 4 + 9 + 16 + 25 = 55. Σ from k = 0 to 3 of 2ᵏ means 1 + 2 + 4 + 8 = 15. The index variable is a dummy — Σ from j = 1 to 5 of j² is the same sum as Σ from i = 1 to 5 of i² — and the limits can start anywhere, including 0 and negative numbers, provided the expression is defined at each value.

Three reading rules prevent the common errors. First, the expression after the sigma applies to the index at each step, not to the whole sum: Σ i² is not (Σ i)². Second, constants factor out: Σ from i = 1 to n of c·aᵢ = c × Σ aᵢ, and Σ of a constant c over n terms is n·c. Third, sums split over addition: Σ (aᵢ + bᵢ) = Σ aᵢ + Σ bᵢ. The calculator on this page evaluates sums from an expression and limits; writing the sum in sigma notation first, and checking the first two and last terms by hand, catches most entry errors before they propagate.

Arithmetic and geometric sums: the closed forms

An arithmetic series — constant difference between terms — sums to n/2 × (first + last). The sum 1 + 2 + … + 100 is 100/2 × 101 = 5,050, the answer Gauss is said to have found as a schoolboy by pairing terms (1 + 100, 2 + 99, …). A geometric series — constant ratio between terms — sums to a × (1 − rⁿ)/(1 − r) for ratio r ≠ 1, where a is the first term and n the number of terms. The sum 1 + 2 + 4 + … + 2⁹ is (1 − 2¹⁰)/(1 − 2) = 1,023. For |r| < 1, the infinite geometric series converges to a/(1 − r): 1 + 1/2 + 1/4 + … = 2.

The closed forms matter because they replace a long addition with one evaluation, and because they reveal structure: the arithmetic sum is quadratic in n (n²/2 for the sum 1 to n), and the geometric sum is exponential in n. They also bound errors: a sum computed term by term accumulates rounding at each step, while the closed form computes once. The calculator uses the closed forms where the series is recognised and term-by-term summation otherwise; the guide’s companion article derives both formulas and shows the convergence behaviour of the infinite cases.

Frequently asked questions

What is a summation calculator?

A summation calculator adds up a whole series of terms at once. You pick a pattern, such as k or k squared, set the start and end values, and it returns the exact total, usually from a closed-form formula rather than by adding every term by hand.

What is the sum of 1 to 100?

The sum of 1 to 100 is 5,050. Using the formula n times n plus 1 divided by 2 with n equal to 100 gives 100 times 101 divided by 2, which is 5,050.

What is the sum of squares from 1 to 10?

The sum of squares from 1 to 10 is 385. Using the formula n times n plus 1 times 2n plus 1 divided by 6 with n equal to 10 gives 10 times 11 times 21 divided by 6, which is 385.

What does Σ(ak + b) mean?

Σ(ak + b) means: for each whole-number value of k in the range, work out a times k plus b, and add all those values together. It splits neatly into a times the sum of k plus b times the number of terms.

What happens if the start is bigger than the end?

If the start value is bigger than the end value, the range is empty in the usual reading, so this calculator shows an error and asks you to fix the range instead of guessing an answer.

Why does the table only show the first 20 terms?

The table is a check, not the calculation. Showing the first 20 terms lets you verify the pattern and the running total, while the sum itself always comes from the closed form, so it stays exact even for a range of 10,000 terms.

Why does the sum from 0 to 100 equal the sum from 1 to 100?

Because the added term is 0, which contributes nothing. The sum of k from 0 to 100 is 5,050, the same as from 1 to 100, but across 101 terms instead of 100. That is a useful sanity check for any range starting at 0: if the total changes when you extend the start down to 0, the pattern’s zero term is not zero, and the range, not the formula, deserves a second look. For k squared and k cubed the zero term is also 0, so the same check applies.

How do I work out 3k + 2 from 1 to 10 without adding ten terms?

Split it: a times the sum of k, plus b times the number of terms. The sum of k from 1 to 10 is 55, so 3 times 55 is 165, and 2 times 10 terms is 20, giving 185 in total, matching the calculator’s display. The same split gives 3k + 2 from 1 to 100 as 15,350: 3 times 5,050 is 15,150, plus 2 times 100 is 200. Every linear pattern on this page splits the same way, which is why the calculator reports its closed form as a times the sum of k plus b times the number of terms.

How do I check a large sum without adding every term?

Check the term count, the first and last terms, and a small case by hand. The number of terms from a to b inclusive is b minus a plus 1, so 1 to 100 has 100 terms and 0 to 100 has 101. The result panel reports the first and last terms, so a last term that does not match your endpoint means the pattern or range is not what you intended. Then compute the same pattern over 1 to 10 by hand: if the small case matches, the formula is right, and any disagreement on a large case is an endpoint error, not a formula error.

Can this calculator sum a geometric series, or a series with fractions?

No. It covers five patterns only: k, k squared, k cubed, a constant, and a linear pattern ak plus b, and it says so openly. A geometric series, or a series with fractions, needs its own tool with its own formula, not a guessed parse of your typing. If your series is not one of the five, the honest move is to use the tool built for it, rather than forcing it into a pattern it does not match and treating the result as an answer.

What is the sum of 1 to 100?

5,050. The arithmetic-series formula gives n/2 × (first + last) = 100/2 × 101 = 5,050. The same pairing argument works for any arithmetic series: pair the first and last terms, and each pair sums to the same total.

What does Σ mean in maths?

Sigma (Σ) denotes a sum. Σ from i = 1 to n of aᵢ means add the values of aᵢ for i = 1, 2, …, n. The variable under the sigma is the index; the numbers above and below it are the upper and lower limits of the sum.

This calculator is an educational tool for working out sums of standard series. It covers five named patterns only, and its results should be checked before being used in any formal work.

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